An object with a height of 40 cm is placed 25 m in front of

An object with a height of 40 cm is placed 2.5 m in front of a concave mirror with a focal length of 0.50 m. Find the location of the image produced by the mirror using the mirror and magnification equations. Express your answer using two significant figures. Find the magnification of the image produced by the mirror using the mirror and magnification equations. Express your answer using two significant figures.

Solution

The equations for mirrors are similar to that of lenses,

So

Part A

1/f=1/do + 1/di

1/di = 1/f - 1/do

1/di = (1/.5) - (1/2.5) = 1.6

di = 1/1.6 = 0.625 m

Part B

m= hi/ho = -di/do

hi = (-di/do)*ho

hi = (-0.625/2.5)*40 = 10cm


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