b Find the rate of dissipation of electrical energy in the b

b) Find the rate of dissipation of electrical energy in the battery.

c) Find the rate of dissipation of electrical energy in the external resistor.

Solution

Here ,

let the current is I

Using KVL

12 - (1 + 5) * I = 0

I = 2 A

a) rate of conversion of internal energy to electrical energy = V * I

rate of conversion of internal energy to electrical energy = 12 * 2 W

rate of conversion of internal energy to electrical energy = 24 W

b)

rate of electrical energy dissipation in battery = I^2 * 1

rate of electrical energy dissipation in battery = 2^2 * 1

rate of electrical energy dissipation in battery = 4 W

c)

rate of energy dissipated in external resistor = I^2 * 5

rate of energy dissipated in external resistor = 2^2 * 5

rate of energy dissipated in external resistor = 20 W

the rate of energy dissipated in external resistor is 20 W