Two small particles have charges Q1 45 C and Q2 70 C If th

Two small particles have charges Q1 = +4.5 C and Q2 = 7.0 C. If the magnitude of the electric force between the particles is 135 N, what is the distance between the particles?

Solution

Force between two electric charge (F) = k*Q₁*Q₂ /d²

135= 9*1000000000* 4.5* 7* /(1000000000000* d²⁾

where k = 9* 1000000000 N*m²/ C²

On solving we get distance between the 2 charges = .0458 m= 45.8 mm