An n x n matrix that is filled with the whole numbers 1 2 3

An n x n matrix that is filled with the whole numbers 1, 2, 3, .. n^2 is a magic square if the sum of the elements in each row, in each column, and in the two diagonals is the same value.

Here is a magic square where n = 3:

8 1 6
3 5 7
4 9 2

Write a program that reads n^2 numbers from standard input and tests whether they form a magic square when put into matrix form. The value of n is NOT an input to the program; n must be determined from the number of inputs.

For example, the input that creates the example matrix above is: 8 1 6 3 5 7 4 9 2.

The output is a single word, \"true\" if the input produces a magic square, \"false\" otherwise. Your program may assume that each input token is a whole number.

The program must verify:

1. The proper number of input values was provided.

2. Each of the numbers between 1 and n2 occurs exactly once in the input.

3. When the numbers are arranged in a matrix,

Solution

public class MagicSquare{ static int rowSum1; static int rowSum2; static int rowSum3; static int rowSum4; static int columnSum1; static int columnSum2; static int columnSum3; static int columnSum4; public static void main(String [] args) { int square[][]={{16,3,2,13}, {5,10,11,8}, {9,6,7,12}, {4,15,14,1}}; // get each rows total for (int i =0; i < 4;i++){ rowSum1 += square[0][i]; } for (int i =0; i < 4;i++){ rowSum2 += square[1][i]; } for (int i =0; i < 4;i++){ rowSum3 += square[2][i]; } for (int i =0; i < 4;i++){ rowSum4 += square[3][i]; } // get each columns totals for (int i =0; i < 4;i++){ columnSum1 += square[i][0]; } for (int i =0; i < 4;i++){ columnSum2 += square[i][1]; } for (int i =0; i < 4;i++){ columnSum3 += square[i][2]; } for (int i =0; i < 4;i++){ columnSum4 += square[i][3]; } // print out, just to make sure it\'s working correctly System.out.println(rowSum1); System.out.println(rowSum2); System.out.println(rowSum3); System.out.println(rowSum4 + \"\ \"); System.out.println(columnSum1); System.out.println(columnSum2); System.out.println(columnSum3); System.out.println(columnSum4); if ((rowSum1 == rowSum2) && (rowSum1 == rowSum3) && (rowSum1 == rowSum4) && (rowSum1 == columnSum1) && (rowSum1 == columnSum2) && (rowSum1 == columnSum3) && (rowSum1 == columnSum4)){ System.out.println(\"Congradulations, you have a magic square!!!!\"); } else { System.out.println(\"You Fail!!!!!!\"); } } }