Mass in grams of 0105 moles of sucrose C12H22O11Solutionfind

find the molar masses of each element, mulitply by the number,then multiply the whole thing by .105 moles

molar mass of C = 12.011 there are 12x C atoms = 144.132

molar mass of H = 1.008      1.008 x22= 22.176

molar mass of O = 15.9994 x 11 = 175.9934

add them:

342.3014   or 342.301

multiply by the # of moles present:

342.301 x .105 = 35.9 g