2-Calculate the percentage composition for each of the followingcompounds (three significant figures).
(a) H
2O
2 H
1%
O
2%
(b) KClO
4 K
3%
Cl
4%
O
5%
(a) H
2O
2 H
1%
O
2%
(b) KClO
4 K
3%
Cl
4%
O
5%
H2O2 = 2*1 + 2*16 = 34 g/mol % H = 2*1 / 34 = 0.0588235294 => 5.88 % % O = (2*16) / 34 = 0.941176471 => 94.1 % ===== KClO4 formula mass = 138.5 g/mol %K = (39.1 / 138.5 ) = 0.282310469 => 28.2 % %Cl = (35.5 / 138.5) = 0.25631769 => 25.6% % O = (4*16)/ 138.5 = 0.462093863 => 46.2 %