Express your answer using twosignificant figuresSolution t

            

t = 2.303/k    log(a₀/a_t), k - rate constant.

      

At t = t_1/2 (i.e., the half life) a_t =a₀/2 .

       

Therefore,

         

t_1/2 = 2.303/k log 2 = 0.693/k.

              

=> k = 0.693/t_1/2

      

Thus, k = 0.693/ 56.3 mins^-1 = 0.693/(56.3*60)sec^-1 = 2.05x10^-4 sec^-1