Homework Sourse2 Two 187 kg masses are 254 m apart center to center on afri
2. Two 1.87 kg masses are 2.54 m apart (center to center) on africtionless table. Each mass has +23.8 C of charge. What isthe magnitude of the electric force on one of the masses? What isthe initial acceleration of this mass if it is released and allowedto move?
Solution
Coulombs law: F = k Q1Q2/r2
Newton\'s 2nd law: F = ma
these two equations are equal to each other.
a = (kQ1Q2)/(mr2)
k = coulomb constant 9x109
Q1 = Q2 = 23.8C
m = 1.87kg
r = 2.54m
Newton\'s 2nd law: F = ma
these two equations are equal to each other.
a = (kQ1Q2)/(mr2)
k = coulomb constant 9x109
Q1 = Q2 = 23.8C
m = 1.87kg
r = 2.54m
plug in and solve to get the answers. hope that helps
