In a population of cattle the following color distribution w

Solution

Hardy-Weinberg equilibrium equation p^2 + 2pq + q^2 = 1 0.81+0.18+0.01 = 1 p = 0.9 q = 0.1 so p+q = 1 This is A Hardy-Weinberg equilibrium . Distribution of genotypes : here p^2 = 0.9*0.9 = .81 2pq = 2*0.9*0.01 = .18 q^2 = 0.1*0.1 = 0.01 ANSWER refrence : http://anthro.palomar.edu/synthetic/sample.htm please rate