Part A Part B Express your answer numerically ininverse seco

Part A The activation energy of a certain reactionis 38.4 kJ/mol. At 20 ^{circ}rm C, the rate constant isrm 0.0130~s^{-1}. At whattemperature would this reaction go twice as fast? Express your answer numerically indegrees Celsius Part B Given that the initial rate constant isrm 0.0130~s^{-1} at an initialtemperature of 20 ^circ rm C, what would the rateconstant be at a temperature of 100 rm ^{circ}C? Express your answer numerically ininverse seconds.

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