a the minimum value of vector Fis N b the normal force exert

(a) the minimum value of vector Fis? N

(b) the normal force exerted by the incline on theblock? N

Solution

   The component F cos acts parallel tothe plane ( towards right side ) and
  the component F sin acts perpendicular tothe plane ( downward )
   Normal reaction, N = mg cos + F sin
   frictional force, f = N = ( mg cos + F sin )
Condition for equilibrium, Net force along the plane inupward direction =
                                             Netforce along the plane in downward direction
                             Fcos = ( mg cos + F sin ) +mg Sin
                                             F ( cos - Sin ) = mg ( Sin + cos )
(a)   Minimum value of F = mg ( Sin + cos ) / ( cos - Sin ) = 27.2N
(b)   Normal force, N = mg cos + Fsin = 33.4 N

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