a the minimum value of vector Fis N b the normal force exert
(a) the minimum value of vector Fis? N
(b) the normal force exerted by the incline on theblock? N
(b) the normal force exerted by the incline on theblock? N
Solution
The component F cos acts parallel tothe plane ( towards right side ) and
the component F sin acts perpendicular tothe plane ( downward )
Normal reaction, N = mg cos + F sin
frictional force, f = N = ( mg cos + F sin )
Condition for equilibrium, Net force along the plane inupward direction =
Netforce along the plane in downward direction
Fcos = ( mg cos + F sin ) +mg Sin
F ( cos - Sin ) = mg ( Sin + cos )
(a) Minimum value of F = mg ( Sin + cos ) / ( cos - Sin ) = 27.2N
(b) Normal force, N = mg cos + Fsin = 33.4 N