A chemist adds 1000mL of a 041M copperII sulfate CuSO4 solut

A chemist adds 100.0mL of a 0.41M copper(II) sulfate CuSO4 solution to a reaction flask. Calculate the mass in grams of copper(II) sulfate the chemist has added to the flask. Round your answer to

2 significant digits.

final answer in grams

Solution

volume , V = 100.0 mL

= 0.1 L

we have below equation to be used:

number of mol,

n = Molarity * Volume

= 0.41*0.1

= 4.1*10^-2 mol

Molar mass of CuSO4 = 1*MM(Cu) + 1*MM(S) + 4*MM(O)

= 1*63.55 + 1*32.07 + 4*16.0

= 159.62 g/mol

we have below equation to be used:

mass of CuSO4,

m = number of mol * molar mass

= 4.1*10^-2 mol * 159.62 g/mol

= 6.544 g

Answer: 6.5 g