44 How m any g of Naci are in 40mL of a solution whose conce

44. How m any g of Naci are in 40mL of a solution whose concentration is 2.5%(mv)? a. 100sg b. 16 g c. 1.0g d. 10 g e. 160 g 550. mL of 0.115 M KBr? (MMK\'= 119.002 45. How many grams of KBr are required to prepare a. 5.65 g b. 7.53 g o. 8.00 9 d. 74.8 g e. 56.5 g Place the following with the weakest intermolecular forces. a. F2 HF HCI b. HF HCI F c. F2 HCI HF d. HCI F2 HF 46. compounds in order of strength of intermolecular forces, starting with the one F2, HF, HCi

Solution

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100 mL of a 2.5%(m/v) solution contains 2.5 g NaCl.

So mass of NaCl is 40 mL of this solution = (2.5/100)*40 = 1 g

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Moles of KBr reqd = Molarity*Volume = 0.115*0.550 = 0.06325

Mass oF KBr reqd = Moles*MW = 0.06325*119.002 = 7.53 g

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The correct order is:

F₂ < HCl < HF

This is because the bond polarity increases in this order, and the higher the polarity, the stronger will be the intermolecular interactions.

Hope this helps !