If Neis heterozygosity h0295 and assuming a 2 allele system

If Nei\'s heterozygosity h=0.295, and assuming a 2 allele system, what is p1 and p2?

Solution

Heterozygosity h = 0.295

Here, p1 + p2 = 1

p1 = 1 - p2

2p1p2 = 0.295

(1-p2)*p2 = 0.1475

p2 - p2^2 - 0.1475

p2^2 - p2 + 0.1475 = 0

By solving the quadratic equation,

p2 = 0.82

p1 = 0.18

or p1 = 0.18

p2 = 0.82