A mechanical engineer wants to make a shaft turn CW by weldi

A mechanical engineer wants to make a shaft turn CW by welding a 15 cm handle to it. The shaft requires a tourque 8.5N m before it will turn. If she applies a force of 50 N to the end of the handle at an angle theta 30 degrees will the shaft turn?

Solution

torque applied is T = r*F*sin(theta)

given that

r = 15 cm = 0.15 m

F = 50 N

theta = 30 deg

then

T = r*F*sin(30) = 0.15*50*sin(30) = 3.75 N-m

but required torque was 8.5 N m

since 8.5 Nm > 3.75 Nm
so the shaft does not turn