Enter your answer in the provided box How many grams of pota

Enter your answer in the provided box. How many grams of potassium chlorate decompose to potassium chloride and 315 mL of O2 at 12s°c and 760. torr?

The ideal gas equation to find the moles of O2.

P= 760 torr (1 atm/760 torr) =1 atm

V=315mL(1L/10^3mL) =0.315 L

T=128 C +273=401K

PV=nRT

n=PV/RT

= (1 atm) (0.315L) / (0.082057L .atm/mol.K) (401K)

=0.315/32.9048

=0.00957 mol O2

Now, chemical equations to find the relative number of moles of KClO3 that reacted.

= 0.00957 mol O2 (2mol KClO3/3 mol O2)

= 0.00638 mol KClO3

The molar mass of potassium chlorate is 122.55 g/mol to find the number of grams that reacted.

= 0.00638mol KClO3 (122.55g KClO3/1 mol O2)

=0.78 g KClO3