Prove or Disprove If xn is a convergent sequence of real num
Prove or Disprove:
If xn is a convergent sequence of real numbers, then xn is a Cauchy sequence of real numbers.
Solution
Let M=A,d be a metric space
Every convergent sequence of real numbers is a cauchy seq of real numbers.
Let xn be a sequence in A that converges to the limit l?A.
Let ?>0.
Then also ?2>0.
Because xn? converges to l, we have:
?N:?n>N:d(xn,l)<?2
In the same way:
?m>N:d(xm,l)<?2
So if m>N and n>N, then:
This completes the proof that xn is a cauchy sequence.
| d(xn,xm) | ? | d(xn,l)+d(l,xm) | (by the Triangle Inequality) | ||||||||||
| < | ?2+?2 | (by choice of N) | |||||||||||
| = | ? |
