Multiply 142five by 2 The number of pieces in the minimal se

Multiply 142_five by 2. The number of pieces in the minimal set are (fill in unused symbols with zero): Multiply 47_eight by 3. The number of pieces in the minimal set are (fill in unused symbols with zero):

Solution

c)
Each LF has 5^3, i.e 125
Each F has 5^2, i.e 25
Each L has 5^1, i.e 5
Each unit has 5^0, i.e 1

142 * 2 gives us 284

Now, 284 can be written as :

284 = 2*125 + 1*25 + 1*5 + 4*1

So, we have :
2 long flats , 1 flat , 1 long and 4 units

So, under longflat, enter 2
Under flat, enter 1
Under long, enter 1
Under units, enter 4

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d)

47 * 3 is 141

Now, one flat has 8^2, i.e 64
One long has 8^2, i.e 8
One unit has 8^0, i.e 1

So, 141 can be written as :

141 = 2*64 + 1*8 + 5*1

So, we have 2 flats , 1 long and 5 units

So, under flats, enter 2
Under longs, enter 1
Under units, enter 5