Find three consecutive multiples of 7 if the sum is 273Solut

Find three consecutive multiples of 7 if the sum is 273.

Solution

Three consecutive multiples of 7 are a*7 , (a + 1)*7 and (a + 2)*7

Their sum is equal to 273

=> a*7 + (a + 1)*7 + (a + 2)*7 = 273

=> a + a + 1 + a+ 2 = 39

=> 3a + 3 = 39

=> a + 1 = 13

=> a = 12

This gives the multiples 84, 91, 98