6 an airplane flies from city A to city B a distance of 150

6.

an airplane flies from city A to city B a distance of 150 miles and then turns through an angle of =40 degrees and heads towards city C, as shown.

a) If the distance between cities A and C is L=300 miles, how far is it from city B to city C? ______ miles

b) through what angle should the pilot turn at city C to return to city A? ________ degree angle.

Solution

according to sin law

sin (140)/300=sinA/150

By solving it we get angle A=18.74

plugging the angle we will have 140+18.74=158.74

sin140/300=sin158.74/x

x= 169.23 miles

a) 169.23 miles

b)= 158.74