Find x logx x2 0 Degree log26 log2xSolution logxx28log26l

Find x logx (x^2 + 0^ Degree) = log2^6 + log2x

Solution

log_x(x²+8)=log₂6+log₂x

log a +log b =log ab

log_x(x²+8)=log₂6x

log_ba=loga/logb

(log(x²+8))/(logx)=(log6x)/log2

we donnot have general logarithmic formulas to calculate directly

by hit and trial x =2

x=2 makes the equation

(log(2²+8))/(log2)=(log6*2)/log2

log12/log2 =log12/log2

so x =2 is the solution