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solve for x values: x^2 - 5x + 6 > 0

x^2 - 5x + 6 > 0

Let us factor:

==> (x-2)(x-3) > 0

Now we have 2 cases:

case(1) :

x-2 > 0 and (x-3) > 0

==> x>2 and x > 3

==> x = (2, inf) intersects (3, inf) = ( 3, inf)

Case(2):

x-2 < 0 and x-3 < 0

x < 2 and x < 3

==> x = (-inf, 2) and (-inf, 3) = (-inf, 2)

==> x = ( -inf, 2) U ( 3, inf)

x = R - [2, 3]