Two angles of a triangle have the same measure and the third

Two angles of a triangle have the same measure and the third angle is

39°

greater than the measure of the other two. Find the measure of each angle.

Let the measure of first angle = x°

So according to question, two angles are same.

Hence measure of second angle = x°

Measure of third angle = x° + 39°

Now, sum of all angles of a triangle = 180°

So, x°+x°+x°+39° = 180°

3x°+39° = 180°

3(x°+13°) = 180°

x°+13° = 60°

x° = 60°-13°

x° = 47°

So measure of first and second angle = 47°

Measure of third angle = 47°+39° = 86°