Given dydx 1sinx what is the function ySolutionTo get the pr

Given dy/dx= 1-sinx, what is the function y?

Solution

To get the primitive y, we\'ll have to compute the indefinite integral of dy.

Int dy = Int (1 - sin x)dx

We\'ll apply the property of integral to be additive:

Int (1 - sin x)dx = Int dx - Int sin x dx

Int (1 - sin x)dx = x + cos x + C

The primitive function y is: y = x + cos x + C.

Given dy/dx= 1-sinx, what is the function y?SolutionTo get the primitive y, we\'ll have to compute the indefinite integral of dy. Int dy = Int (1 - sin x)dx We\

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