The breaking strength of a rivet has a mean value of 10000 p

The breaking strength of a rivet has a mean value of 10,000 psi and a standard deviation of 500 psi. What is the probability that the sample mean breaking strength for a random sample of 40 rivets is between 9900 and 10,200? If the sample size had been 15 rather than 40, could the probability requested in part (a) be calculated from the given information? Explain. A random sample of n = 8 E-glass fiber test specimens of a certain type yielded a sample mean interfacial shear yield stress of 30.2 and a sample standard deviation of 3.1. Compute a 95% CI for true average stress? (Assume the population has a normal distribution).

Solution