Run the appropriate analysis in Excel and then write a short
Run the appropriate analysis in Excel and then write a short paragraph to answer the question. The paragraph should include:
1. The null and alternative hypothesis
2. The results of your Excel analysis including t-statistics, critical values, and p-values
3. Interpretation of these results
4. Final answer to the question.
Question: Males from the sample were expected to have a FEV of 3.81 L based on their average height and age. Did the male smokers in the sample have an average FEV less than 3.81 L?
Here are the FEV levels for male smokers:
| 1.694 |
| 1.953 |
| 2.276 |
| 2.304 |
| 3.082 |
| 3.339 |
| 3.343 |
| 3.406 |
| 3.498 |
| 3.688 |
| 3.727 |
| 3.751 |
| 3.799 |
| 3.957 |
| 4.045 |
| 4.07 |
| 4.086 |
| 4.27 |
| 4.309 |
| 4.404 |
| 4.506 |
| 4.637 |
| 4.756 |
| 4.763 |
| 4.789 |
| 4.872 |
Solution
Here,
xo = 3.81
x = 3.74
s = 0.79
n= 26
Now,
Null hypothesis : Ho : xo = x
Alternative hypothesis: Ha : xo is not equal to x.
t = (x-xo)/(s/sqrt(n))
t = (3.74 - 3.81) /(0.79/sqrt(26))
t = 6.33
Critical values,
for 0.05 alpha,
tcr = 2.056
So,
null hypotheis can be rejected.
Hence, alternative hypothesis is rejected.
so there is much difference between these two samples.
| 1.694 | |
| 1.953 | |
| 2.276 | |
| 2.304 | |
| 3.082 | |
| 3.339 | |
| 3.343 | |
| 3.406 | |
| 3.498 | |
| 3.688 | |
| 3.727 | |
| 3.751 | |
| 3.799 | |
| 3.957 | |
| 4.045 | |
| 4.07 | |
| 4.086 | |
| 4.27 | |
| 4.309 | |
| 4.404 | |
| 4.506 | |
| 4.637 | |
| 4.756 | |
| 4.763 | |
| 4.789 | |
| 4.872 | |
| Mean = | 3.743231 |
| Sd = | 0.791153 |

