May rides her bike the same distance that leah walks may rid

May rides her bike the same distance that leah walks. may rides her bike 10 km/h faster than leah walks. if it takes may 1 h and leah 3 h to travel that distance, how fast does each travel?

Solution

May DATA:
time = 1 hr. ; rate = x+10 mph ; distance = rt = (x+10)*1 mi
--------------------
Leah DATA:
time = 3 hr. ; rate = x mph ; distance = rt = 3x mi
-----------------------
Equation:
distance = distance
x+10 = 3x
2x = 10
x = 5 mph (Leah\'s rate)
x+10 = 15 mph (May\'s rate)