Five friends are gathered each with a die They each roll a d

Five friends are gathered, each with a die. They each roll a die. What is the probability that one or more of them will get a “four?”

Solution

Prob. of getting a \"4\" from a single die= 1 / 6 and prob. of not getting a \"4\" from a single die= 5/6
So, this is a binomial distribution with n=5 (as there are 5 dice) and p = 1/6....
x= total no. of \"4\"s when all of them rolled their respective die!

Since, the outcomes of each die is independent of each other hence,

Prob [ 1 or more of them will get a \"4\" ] = 1 - p(no one gets a \"4\") = 1 - [ (5c5)(1/6)^0 * ( 5/6 )^5 ]
= 0.598122428