The mean emission of all engines of a new design needs to be
Solution
Formulating the null and alternative hypotheses,              
               
 Ho:   u   >=   20  
 Ha:    u   <   20  
               
 As we can see, this is a    left   tailed test.      
               
 Thus, getting the critical t,              
 df = n - 1 =    9          
 tcrit =    -2.306 [as in your table]      
               
 Getting the test statistic, as              
               
 X = sample mean =    17.17          
 uo = hypothesized mean =    20          
 n = sample size =    10          
 s = standard deviation =    2.981442604          
               
 Thus, t = (X - uo) * sqrt(n) / s =    -3.001649526          
               
 As t < -2.306, we   REJECT THE NULL HYPOTHESIS.  
Thus, there is significant evidence that the mean emission is below 20ppm and it satisifes the new emission requirements. [CONCLUSION]

