The mean emission of all engines of a new design needs to be
Solution
Formulating the null and alternative hypotheses,
Ho: u >= 20
Ha: u < 20
As we can see, this is a left tailed test.
Thus, getting the critical t,
df = n - 1 = 9
tcrit = -2.306 [as in your table]
Getting the test statistic, as
X = sample mean = 17.17
uo = hypothesized mean = 20
n = sample size = 10
s = standard deviation = 2.981442604
Thus, t = (X - uo) * sqrt(n) / s = -3.001649526
As t < -2.306, we REJECT THE NULL HYPOTHESIS.
Thus, there is significant evidence that the mean emission is below 20ppm and it satisifes the new emission requirements. [CONCLUSION]
