A squareroot of fx ex 2x2 lies in the interval 1 2 Determi

A squareroot of f(x) = e^x - 2x^2 lies in the interval (1, 2). Determine this squareroot with the Newton-Raphson method to five decimal accuracy.

Here we take the formula of Newton raphson method

X_n+1=x_n-f(x_n)/f\'(x_n)

Then it will be x=1

X1=1

X2=2

X3=2.5

X4=2.55 something

X5=2.7....... and

X1=2

X2=2.5

X3=2.7....

X4=2.75....

X5=2.8......

The above formula by root of f(x)=e^x-2x² with the intervals (1,2)

are following by the method the decimals are formed.