find the standard normal distributions shown on right find t

find the standard normal distributions shown on right, find the probability of z occurring in the indicated region. one side is marked -1.79 and the other is marked 0.24.

Solution

From z-table area left to z-score -1.79 is 0.0367.

Area left to z-score 0.24 is 0.5948 so area right to z-score is 1-0.5948=0.4052.

Therefore the probability of z occurring in the indicated region is 0.0367+0.4052=0.4419.