Homework SourseWhat is an equation for the plane with a normal vector 111 u
What is an equation for the plane with a normal vector (1,-1,1)? use answer H only if a candidate exist but is not listed below.
A) x+y+z=3
B) x-y+z=3
C) x+y-z=3
D)-x+y+z=3
E) x-y+z=1
F) x-y-z=1
G) there is no such plane
H) there is such a plane but it is none of these
A) x+y+z=3
B) x-y+z=3
C) x+y-z=3
D)-x+y+z=3
E) x-y+z=1
F) x-y-z=1
G) there is no such plane
H) there is such a plane but it is none of these
Solution
The plane equation is:
1(x-1)-1(y+1)+1(z-1) = 0
x-y+z = a+c-b = 1 + 1 - (-1) = 3
Answer B.
