determine without graphing whether the given quadratic funct

determine, without graphing, whether the given quadratic function has a maximum value or a minimum value and then find tht value f(x) = x2 - 2x - 5

Solution

f(x) = x2 - 2x - 5

Its a quadratice function with upwards facing as a>0

The vertex point gives the max/min, values.

Since a>0 , upward facing parabola with minimum value.

f(x) = x^2 -2x -5

vertex = ( h,k)

h = -b/2a = 2/(2*1) =1

k = f(1) = 1 -2 -5 = -6

So, minium value = -6