Use following exmaple for the next questions Please provide

Use following exmaple for the next questions. Please provide an explanation as well:

In spring 2015, 120 students of Psychology Program at Yale University took the Neuropsychology course. Seven of these students received 92, 80, 88, 67, 81, 75 and 70 for the final exam. Which method can the professor use to check his idea?

A. Hypothesis testing - Z test for mean

B. Hypothesis testing - Z test for proportion

C. Hypothesis testing - t test for mean

D. Hypothesis testing - t test for proportion

If we want to conducts hypothesis testing and test if students of Psychology Program at Yale University receive more than 75 on average for the Neuropsychology course, we have to consider:

A. one-tailed test

B. two-tailed test

C. one-tailed test because sample size is large

D. two-tailed test because sample size is large

What is the computed value (closest) of “test statistics” (either z or t) for this study?

A. 0.99

B. 0.02

C. 1.16

D. 1.26

The P-value of this study is:

A. . between 2.5% and 5%

B. between 1% and 2.5%

C. between 15% and 20%

D. between 12.5% and 25%

E. 12.3%

At 5% level of significance, can we conclude that students of Psychology Program at Yale University receive more than 75 on average for the Neuropsychology course?

A. Yes (Reject null hypothesis).

B. No (Reject null hypothesis).

C. Yes (Fail to reject null hypothesis).

D. No (Fail to reject null hypothesis).

Solution

Set Up Hypothesis
Null, H0: U<75
Alternate, H1: U>75
Test Statistic
Population Mean(U)=75
Sample X(Mean)=79
Standard Deviation(S.D)=9.0921
Number (n)=7
we use Test Statistic (t) = x-U/(s.d/Sqrt(n))
to =79-75/(9.0921/Sqrt(6))
to =1.164
| to | =1.164
Critical Value
The Value of |t | with n-1 = 6 d.f is 1.943
We got |to| =1.164 & | t | =1.943
Make Decision
Hence Value of |to | < | t | and Here we Do not Reject Ho
P-Value :Right Tail - Ha : ( P > 1.164 ) = 0.14431
Hence Value of P0.05 < 0.14431,Here We Do not Reject Ho

Q1.
C. Hypothesis testing - t test for mean
Reason: Sample Standadrd deviation can be
calculated in result. We use t-test when sample
s.d is knnown

Q2.
A. one-tailed test
Reason: Here Alternative is defined to receive more than 75
on average for the Neuropsychology course.
Which is right tailed test.

Q3.
to =1.164

Q4.
D. between 12.5% and 25%

Q5.
D. No (Fail to reject null hypothesis).