Lim f x g x s right arrow 0 lim df xdx dg x dx right arrow
Lim [f (x)/ g (x) s right arrow 0 = lim [df (x)/dx /dg (x)/ dx] right arrow 0 show that the expression derive for Pf part b of Example Problem 1.1 has the correct limit as y right arrow 0. (In case, you don?t have time to buy the textbook yet, I attach below the scan of the Examples 1.1 7.1 for your reference.)
Solution
TWO POINTS ..
1.. EX. 1.1 OF 7.1 IS NOT UP LOADED ..SO WE CAN NOT ANSWER.
2. EVEN THE FIRST PART IS TRUE ONLY IF SOME CONDITIONS ARE MET ....NOT OTHER WISE ..
FOR EX.... TAKING ...F[X]=X+4......G[X]=X+2....WE HAVE .....F\'[X]=1......G\'[X]=1....
SO .....LT [ {F(X)} / {G(X)} ] AS X TENDS TO ZERO =
LT [ (X+4)/(X+2) ] AS X TENDS TO ZERO = 2
IT IS NOT SAME AS ...
.LT [ {F\'(X)} / {G\'(X)} ] AS X TENDS TO ZERO =
LT [ 1 / 1 ] ] AS X TENDS TO ZERO = 1 ...
SO PLEASE CHECK BACK YOUR QUESTION & COME BACK
![Lim [f (x)/ g (x) s right arrow 0 = lim [df (x)/dx /dg (x)/ dx] right arrow 0 show that the expression derive for Pf part b of Example Problem 1.1 has the corr Lim [f (x)/ g (x) s right arrow 0 = lim [df (x)/dx /dg (x)/ dx] right arrow 0 show that the expression derive for Pf part b of Example Problem 1.1 has the corr](/WebImages/1/lim-f-x-g-x-s-right-arrow-0-lim-df-xdx-dg-x-dx-right-arrow-965226-1761494778-0.webp)