A sample space S consists of five simple events with their p
A sample space S consists of five simple events with their probabilities
P(E1) = P(E2) = 0.15, P(E3) = 0.4, and P(E4) = 2P(E5)
Find the probability for simple events E4 and E5
Find the probabilities for these two events
A = {E1, E3, E4}B = {E2, E3}
Solution
Sum of P(Ei) = 1 for all i.
Hence 0.15 + 0.15 + 0.4 + 3P(E5) = 1
or P(E5) = 0.1 and P(E4) = 0.2
Now, P(A) = sum of P(Ei) for i = 1, 3, 4
= 0.15 + 0.4 + 0.2 = 0.75
Similarly P(B) = sum of P(Ei) for i = 2, 3
=0.15 + 0.4 = 0.55
