A sample space S consists of five simple events with their p

A sample space S consists of five simple events with their probabilities

P(E1) = P(E2) = 0.15, P(E3) = 0.4, and P(E4) = 2P(E5)

Find the probability for simple events E4 and E5

Find the probabilities for these two events

A = {E1, E3, E4}B = {E2, E3}

Solution

Sum of P(Ei) = 1 for all i.

Hence 0.15 + 0.15 + 0.4 + 3P(E5) = 1

or P(E5) = 0.1 and P(E4) = 0.2

Now, P(A) = sum of P(Ei) for i = 1, 3, 4

= 0.15 + 0.4 + 0.2 = 0.75

Similarly P(B) = sum of P(Ei) for i = 2, 3

=0.15 + 0.4 = 0.55

A sample space S consists of five simple events with their probabilities P(E1) = P(E2) = 0.15, P(E3) = 0.4, and P(E4) = 2P(E5) Find the probability for simple e

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