The symbol is the dereferencing operator The symbol means a

The symbol is the dereferencing operator. The symbol means \" address of.\" The name of an array, without any brackets, acts as a(n) to the starting address of the array. An operator that allocates a dynamic variable is An operator that deallocates a dynamic variable is Parameters that are passed by are similar to a pointer variable in that they can contain the address of another variable. The are used as parameters of a procedure (void function) whenever we want a procedure to change the value of the argument. Given the following information, fill the blanks with either \" an address\" or \"3.75\". float * pointer; float pay = 3.75; pointer = &pay; cout

Solution

1.   The * symbol us the dereferencing operator.
   •   It is unary * operator used in the case of pointers
   •   It is also called as indirection operator. It uses the pointer variable for the know about location value that points in the memory.

2.   The & symbol means “address of”.

   •   It is & is an address operator.
   •   It returns the memory address of the variable.  
   •   These address operators known as pointers.

3.   The name of an array, without any brackets ,acts as a(n) pointer to the starting address of the array.
   •   Pointer variable which can store the address of another variable.

4.   An operator that allocates a dynamic variable is new
   •   This new operator will be used to allocate memory dynamically.
   •   Memory allocation for any data type is possible with new operator.
   •   Like built in operators double ,integer and so on.

5.   An operator that deallocates a dynamic variable is delete
   •   This delete operator will be used to deallocate memory dynamically.
   •   Deallocation means the clean up of the space used for the variable.

6.   Parameter that are passed by addresses are similar to a pointer variable in that they can contain the address of another variable. They are used as parameters of a procedure(void function) whenever we want a procedure to change the value of the argument.
   •   Parameters with address operators are passed to function that is called pointers.
   •   Pointers which can store the address of the other variable.

float *pointer;

float pay = 3.75;

pointer = &pay;

7.   cout <<pointer ; will print 0x7fffb4853014 (address of pointer variable)

   •   it will display the address of the variable.

8.   cout << *pointer; will print 3.75

   •   It will print the value of the pointer variable.
   •   Assign the pay value with address operator(&) to pointer variable.
   •   That means accessing with * unary operator of the pointer variable it will display the value.

9.   cout<< &pay; will print 0x7fff20a35e74sh-4.2
   •   it will display the address of the pay variable type of float.

10.   cout << pay; will print 3.75
   •   it will display the value of the variable type of pointer