A and B are events with PA034 and PB055 Find the probablilit
A and B are events with P(A)=0.34 and P(B)=0.55
Find the probablilities if A and B are disjoint (AnB=0)
a.) P(AnB)
b.)P(AUB)
c.)P(A n not B)
Solution
A and B are events with P(A)=0.34 and P(B)=0.55
Find the probablilities if A and B are disjoint (AnB=0)
P( A n B) = P( A) *P(B) = 0.34*0.55=0.187
b.)P(AUB)
P(AUB) = P( A) +P(B)- P( A n B)
=0.34+0.55-0.187 =0.703
c.)P(A n not B)
P(not B) = 1- P(B) =0.45
P(A n not B) = P( A)* P(nB) = 0.34*0.45 =0.153
