mim Solution1 Truss is stable if mr2j 0 where m number of

Solution

1) Truss is stable if (m+r-2j) >= 0.

where m = number of members

r= number of reactions.

j = number of joints.

for this truss ( 8+4-2*6) =0. Hence this truss is stable.

This is determinate truss. degree of indeterminacy is 0 (m+r-2j=0)

2) m+r-2i = 5+3-2*4 = 0

This is a stable truss and determinate truss. Degree of indeterminacy is zero.