What is the maximum torque that can act on it Answer in unit

What is the maximum torque that can act on it? Answer in units of N m.

An 5.07 m long copper wire with a cross-sectional area of 0.0001324 m^2, in the shape of a square loop, is connected to a 0.1323 V battery. The resistivity of copper is 2.8 times 10^-8 ohm m. If the loop is placed in a uniform magnetic field of magnitude 0.514 T, what is the maximum torque that can act on it? Answer in units of N m.

Solution

R = rho*L/A
= (2.8*10^-8)*(5.07)/(0.0001324)
= 1.072*10^-3 ohm

I = E/R
= 0.1323 / (1.072*10^-3)
=123.39 A

let each side of wire be a
4*a = 5.07
a = 1.2675 m
Area, A = a^2 = 1.2675^2 = 1.61 m^2

T = I*A*B
= 123.39 * (1.61)*0.514
= 101.9 Nm
Answer: 101.9 Nm