Given a 480V battery and 154 and 960 resistors find the powe

Given a 48.0-V battery and 15.4- and 96.0- resistors, find the power of the battery when the resistors are connected in parallel. (Answer in Watts)

Solution

Req = R1*R2/(R1+R2) when connected in parallel ......

=> Req = 15.4*96)/(15.4+96) = 13.271 ohm

power = V^2/Req = 48^2)/(13.271 = 173.61 watt