1 Calculate the voltage from point A to b using Thevenins Th

1- Calculate the voltage from point A to b using Thevenin\'s Theorem.
2- Verify your answer to part (1) using Multisim. Show the circuit and meters reading proper values.

Solution

Solution

560 + 560 = 1120     

1.0 k + 1.0 k = 2000

1120 1000 = = 528.3019

560 2000 = = 437.5

528.3019 + 437.5 = 965.8019

965.8019 910 = = 468.5355

468.5355 + 56 = 524.5355

524.5355 560 = = 270.8439

Therefore, Equivalent Resistance = 270.8439

Solution

Let, be the current through the 910

Then,

I = = = 0.2215 A

Current through (56 ) = * 0.2215 = 0.1144 A

Therefore, current through the 910 resistor

      = * 0.1144

         = 0.0589 A

Solution

Current entering at point B = 0.1144 – 0.0589 = 0.0555 A

Using KCL

      =

                 Or, 2 = ……………….(1)

Now,

        0.0555 = +

Or,   0.0555 = +

Or,   0.0555 = ( + )

Or, 0.0555 = (0.0046)

                 = 12.1406 V

                  = 24.2812V

Therefore,

- = 12.1406 V

2. In the following circuit

Solution

+ + = 100 + 680 + 100 = 880

880 820 = = 424.4706

424.4706 + 220 + 220 = 864.4706

864.4706 820 = 420.8241

420.8241 + 100 + 100 = 620.8241

Therefore, the total resistance between A and B = 620.8241

Solution

Using KVL

       -10 + 100 + + 100 = 0

Or, + 200 = 10…………………… (1)

Or, 200 * + = 10

It gives,

                 = 0.0083 A

                 = 0.0161 A

     = - = 0.0161 – 0.0083 = 0.0078 A

Therefore, = *

                     =

                     = 0.004 A

Solution

= = 0.0078 A

Therefore, the voltage drop across =

                                                             = 220(0.0078)

                                                             = 1.716 V