Given that a receptor responds to epinephrine in a classical

Given that a receptor responds to epinephrine in a classical manner (no homotropic allostery and % occupancy = % efficacy), the cells show 50% activity when the hormone level is 10 nM. What is the % activity at 10 nM epinephrine of cells with a mutated form of the receptor where the Kd is shifted to 150nM?

Solution

In the first sitution %occupancy=%efficacy, it means 50% activity is shown that means 50% occpacy is shown by the hormons.

Kd is the dissociatin constant if it increased that means dissociation also incresed and occpacy will decreased then %efficacy also be reduced. here it incresed to 150nM. if we assume that without mutataion it one than it incresed 150 times than efficay will decreased by 150 times means %activity also decresed with 150 times if it is no homotropic allostery. but it is only assumption for the accuarte information for the activity we must know the Kd for nonmutant reaction