A product with a lot size of 100 parts goes through a work c

A product with a lot size of 100 parts goes through a work cell to complete the machining operation. Determine the cycle time (through the cell) in minutes for each part using the following data Given: setup time = 2.5 hours/100 parts queue, move, and transport =.9 hours/10 pallets run time = 22 mins/part 1.5 min 5.4 min 22 min 29 min 37 min 40 min The inventory turns for a product with $2,000,000 in COGS (cost of goods sold) changes from 10 to 150 due to improved production operations. What are the annual interest savings if the interest rate on. The short-term loans used to finance the inventory is 7 percent?

Solution

Lot size=100

Cycle time=?

a) set up time=2.5 Hr/100 part

therefore,

set up time=2.5*60/100 (min/part)

set up time=1.5 min/part

b) Transportation time=0.9 Hr/10 pallets

therefore,

Transportation time=0.9*60/10 (min/part)

Transportation time=5.4 min/part

c) Run time=22 min/part

Therefore cycle time= Total time required to complete on part

cycle time=set up time per part+Transportation time per part+Run time per part

cycle time=1.5+5.4+22=28.9 min/part which is equivalent to 29 min/part