An organism with the genotype AaBbCCdd is crossed with one t

An organism with the genotype AaBbCCdd is crossed with one that is AAbbccDd. What are the odds of having an offspring with the genotype AabbCcDd. In this problem, do not use Punnett squares. Solve the problem using math and statistics and make sure you Some dogs bark while trailing; others are silent. The barker gene is dominant, the silent gene recessive. The gene for normal tail is dominant over the gene for screw (curly) tail. A barker dog with a normal tail who is heterozygous for both characteristics is mated to another dog of the same genotype. What fraction of their offspring will be barkers with screw tails? Answer this using the probability method: do not do a Punnet square!

Solution

Answer:

22). AaBbCCdd x AabbccDd

Aa X AA = AA (1/2), Aa(1/2)

Bb X bb = Bb(1/2), bb(1/2)

CC X cc = Cc(1)

dd X Dd = Dd (1/2), dd(1/2)

The probability of AabbCcDd genotype = 1/2 * 1/2 * 1 * 1/2 = 1/8

23). 3/16

Barker = B

Silent = b

Normal tail = T

curly tail = t

BbTt x BbTt

Bb X Bb = BB (1/4), Bb (1/2), bb (1/4) or b_= 3/4 & bb= 1/4

Tt X Tt = TT (1/4), Tt (1/2), tt (1/4) or T_ 3/4 & tt (1/4)

barker & screw probabilty (B_tt)= 3/4 * 1/4= 3/16