Out of a standard 52 deck of cards 5 are chosen without repl

Out of a standard 52 deck of cards, 5 are chosen without replacement. What is the probability of getting at least 2 kings but no aces or jacks.

please show work.

P(2 kings but no aces or jacks) = (4c2) * (40C3) / 52C5 = 19/833

P(3 kings but no aces or jacks) = (4C3) * (40C2) / 52C5 = 1/833

P(4 kings but no aces or jacks) = 0.0000153907716933

So, P(atleast 2 kings but no aces or jacks) = 19/833 + 1/833 + 0.0000153907716933

= 0.024 approx