On the tingold phase diagram below only singlephase regions
Solution
solution:
1)here for given tin gold equillibrium diagram comprises of eutectic,peritectic and eutectoid transformation to achieved final state of solution from liquid to solid.
2)here various state nomenclature for this answer is
tau=t
eta=e
alpha=a
beta=b
gamma=g
delta=d
2)here for peritectic transformation occure at temperature of 400 c and 95% composition andgive liquid +solid get converted to another solid
L+s1=s2
L+e=e+(t+e)+t+(t+L)
here phases are
#1=L+e
#2=t+e
#3=L+t
3)here eutectic transformation occure at 80% and 200 C,liquid get converted into another two solids
L=S+S
(L+S3)+(L+t)=S3+t
here phases are
#4=L+S3
#5=L+t
5)here eutectoid transformation occure at 45% and 300 c we get one solid get converted another two solid
S1=S2+d
#6=d
6)here eutecoid transformation occure at 30% and 250C we get
S2=(L+b)+g=b+g
7)here in this way liquid get onverted into final solid composition through intermediate solid as shown in reaction
8)terminal states are
b=beta
g=gamma
d=delta
S3+t
t
t+e
e
in this way this final state achieved at various composition on cooling to room temperature
