The information on the can of pop indicates that the can con

The information on the can of pop indicates that the can contains 355mL. The mass of the full can of pop is 0.369kg, while an empty can weights 0.153 N. Determine the specific weight, density and specific gravity of pop and compare your result with the corresponding value of water at T = 20 degree C.

Solution

Mass of the empty Can = 0.153/9.8 = 0.0156 kg

Mass of the Pop = 0.369- 0.0156 =0.3534 kg

Weight of the Pop =0.3534 * 9.8 =3.46332 N

Volume of Pop = 355 mL = 3.55 *10-4 m3

Density of Pop = 0.3534/3.55*10-4 = 995.5 kg/m3

Specific Gravity = 995.5/1000 = 0.9955

Specific Weight = Weight /Volume = 975.58 N/m3

 The information on the can of pop indicates that the can contains 355mL. The mass of the full can of pop is 0.369kg, while an empty can weights 0.153 N. Determ

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