C programming code that counts the number of digits in strin

Problem 2 A function that calls another function, which in turn calls the original function, is said to be corecursive. Note that corecursive functions occur in pairs. Write a program that counts the number of digits in a string and sums the characters (ASCII code) in the string. For example, the string \"Ai444apple7\" has five digits, and the characters in the string sum to 599. Write a pair of corecursive functions to help carry out the tasks. Use count dig0 to count the alphabetic characters, and use sum_char for summing the digits. These two functions should call each other. For comparison, write a non-corecursive function that performs the two tasks in a direct, more natural fashion. Hint: If necessary, use static variables.

Solution

//C programming code that counts the number of digits in strings and sums the characters.

#include <stdio.h>
void main()
{
char string[80];
int countdigit,sum = 0,len;

printf(\"Enter the string containing both digits and alphabet \ \");
scanf(\"%s\", string);
len = strlen(string);
countdigit = count_digit(string);
sum = sumCharacter(string, 0)
printf(\"NO. of Digits in the string = %d\ \", nc);
printf(\"The sum of all ascii values in \'%s\' is %d.\ \", string, sum);
}

int sumCharacter(char str[], int num)
{
if (num < strlen(str))
{
return (str[num] + sumascii(str, num + 1));
}

return 0;
}

int count_digit(char str[]){
int count, nc = 0;
for (count = 0; string[count] != \'\\0\'; count++)
{
if ((string[count] >= \'0\') && (string[count] <= \'9\'))
{
nc += 1;
}
}
return nc;
}

Thank you.